GNU C++ Compiler
	Debugging: Warnings

control reaches end of non-void function '?'

Function '?' promised to return a value, but there is at least one way to get through the function without executing a return statement. Good structured programming style dictates that each function should have at most 1 return statement, which should be the very last statement in the function.

implicit declaration of function `?'

This is a serious error.

1. If this is a library function, make sure you have #include'd the necessary header file (use the man command to find out what header file you need).
2. If this is a function you have written yourself, make sure you have a prototype for it. Also, check that you've spelled all names the same way everywhere--function prototypes, calls and definitions (remember that case matters).

statement with no effect

Means just what it says--this statement does absolutely nothing useful; check to see if you forgot an = as part of a compound operator (+=, -=, etc.)

suggest parentheses around assignment used as truth value

Check for '=' where you really mean to use '==' (especially in conditional expressions like if, while, for, etc.)

unknown escape sequence `\?'

Only the following characters may follow a backslash: 0, a, b, n, t, x##, \, ".

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