- zero, one, two, three, four, five, six, seven, eight, nine, ten.
- 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
- zero. Because I'm weird. Most will start with one and that's ok.
- If we are counting, eleven (11). Otherwise, there is no next number.
- Again, If we are counting, and start with 0, there are 10, one for each digit.
| 89-x | = | 100 |
| x | = | -11 |
Another way to solve this question is to set it up as:
| 19 | |
| - | 89 |
| 11 |
| 1 | 4 | 2 | 8 | 5 | 7 | R | 1 | |||
| 7 | / | 1 | 0 | 0 | 0 | 0 | 0 | 0 | ||
| - | 7 | |||||||||
| 3 | 0 | |||||||||
| - | 2 | 8 | ||||||||
| 2 | 0 | |||||||||
| - | 1 | 4 | ||||||||
| 6 | 0 | |||||||||
| - | 5 | 6 | ||||||||
| 4 | 0 | |||||||||
| - | 3 | 5 | ||||||||
| 5 | 0 | |||||||||
| - | 4 | 9 | ||||||||
| 1 | ||||||||||
142857 r1
For problems 9-11: Given A={m,a,t,h} and B = {e,a,s,y}.
B.
A. {a,e,h,m,s,t,y} (However, remember order is not important).
A. {b,c,d,e,f,g,i,j,k,l,n,o,p,q,r,s,u,v,w,x,y,z}. May possibly include A,B,C...,1,2,3...
B and A 
B
A. A B =
{x|x < 3 or x > 4} and A
B =
.
Describe in words B
C
and B C.
A. B C = {youths attending BCYF together with BCM&SC students}
and
B C = {BCM&SC students attending BCYC}
- Complement of (A B) = complement of A complement of B. Answer: FALSE.
- (A B) C = A (B C). Answer: TRUE
- A (B C) = (A B) (A C) Answer: FALSE. It can be made true by changing the second half of the equation to (A B) (A C)